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The range of thresholds for diameter 2 in random Cayley graphsPrimeFaces.cw("AccordionPanel","widget_formSmash_some",{id:"formSmash:some",widgetVar:"widget_formSmash_some",multiple:true}); PrimeFaces.cw("AccordionPanel","widget_formSmash_all",{id:"formSmash:all",widgetVar:"widget_formSmash_all",multiple:true});
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PrimeFaces.cw("AccordionPanel","widget_formSmash_responsibleOrgs",{id:"formSmash:responsibleOrgs",widgetVar:"widget_formSmash_responsibleOrgs",multiple:true}); 2014 (English)In: European journal of combinatorics (Print), ISSN 0195-6698, E-ISSN 1095-9971, Vol. 35, 141-154 p.Article in journal (Refereed) Published
##### Abstract [en]

##### Place, publisher, year, edition, pages

2014. Vol. 35, 141-154 p.
##### National Category

Mathematics
##### Identifiers

URN: urn:nbn:se:umu:diva-82279DOI: 10.1016/j.ejc.2013.06.030ISI: 000324786900014OAI: oai:DiVA.org:umu-82279DiVA: diva2:697448
##### Conference

6th European Conference on Combinatorics, Graph Theory and Applications (EuroComb), AUG 29-SEP 02, 2011, Budapest, HUNGARY
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Available from: 2014-02-18 Created: 2013-10-29 Last updated: 2014-02-18Bibliographically approved

Given a group G, the model g(G, p) denotes the probability space of all Cayley graphs of G where each element of the generating set is chosen independently at random with probability p. Given a family of groups (G(k)) and a c is an element of R+ we say that c is the threshold for diameter 2 for (G(k)) if for any epsilon > 0 with high probability Gamma is an element of g(G(k), p) has diameter greater than 2 if p <= root(c - epsilon)log n/n and diameter at most 2 if p >= root(c + epsilon)log n/n. In Christofides and Markstrom (in press) [5] we proved that if c is a threshold for diameter 2 for a family of groups (G(k)) then c is an element of [1/4, 2] and provided two families of groups with thresholds 1/4 and 2 respectively. In this paper we study the question of whether every c is an element of [1/4, 2] is the threshold for diameter 2 for some family of groups. Rather surprisingly it turns out that the answer to this question is negative. We show that every c is an element of [1/4, 4/3] is a threshold but a c is an element of (4/3, 2] is a threshold if and only if it is of the form 4n/(3n - 1) for some positive integer n.

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